Une parcelle de terrain rectangulaire a une longueur qui est 3 fois sa largeur. Si la diagonale de la parcelle est de 60 mètres, quelle est la largeur de la parcelle ? - discuss
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Une parcelle de terrain rectangulaire a une longueur qui est 3 fois sa largeur. Si la diagonale de la parcelle est de 60 mètres, quelle est la largeur de la parcelle ?
*What formula applies to this shapeThis calculation aligns with mobile-first learning styles, where short, clear explanations support quick comprehension without overwhelming detail.
In many urban and semi-rural U.S. regions, rectangular parcels with length-to-width ratios like 3:1 represent an efficient balance between buildable space and lot depth. Real estate profiling increasingly highlights such proportional efficiencies, especially where land is fragmented or shaped by zoning constraints. The 60-meter diagonal measurement—approximately 197 feet—fits naturally into medium-scale parcel zones, making it a common archetype in suburban expansion patterns. ( 10W^2 = 3600 )( W = \sqrt{360} = 6\sqrt{10} ) meters—about 18.97 meters.
The Geometry Behind the Question
( W^2 + 9W^2 = 3600 )
( W^2 = 360 )
The Geometry Behind the Question
( W^2 + 9W^2 = 3600 )
( W^2 = 360 )
Why This Ratio Is Trending in the U.S. Market
If a rectangular plot has length (L) three times its width (W), and its diagonal measures 60 meters, we apply the Pythagorean theorem. The diagonal divides the rectangle into two right triangles with sides W, 3W, and hypotenuse 60. Using ( W^2 + (3W)^2 = 60^2 ),
